解答题
1.把下列各式分解因式:
①a2+10a+25 ②m2-12mn+36n2
③xy3-2x2y2+x3y ④(x2+4y2)2-16x2y2
2已知x=-19,y=12,求代数式4x2+12xy+9y2的值.
3.已知│x-y+1│与x2+8x+16互为相反数,求x2+2xy+y2的值.
答案:
①(a+5)2;②(m-6n)2;③xy(x-y)2;④(x+2y)2(x-2y)2
2019-05-27试题
解答题
1.把下列各式分解因式:
①a2+10a+25 ②m2-12mn+36n2
③xy3-2x2y2+x3y ④(x2+4y2)2-16x2y2
2已知x=-19,y=12,求代数式4x2+12xy+9y2的值.
3.已知│x-y+1│与x2+8x+16互为相反数,求x2+2xy+y2的值.
答案:
①(a+5)2;②(m-6n)2;③xy(x-y)2;④(x+2y)2(x-2y)2